Three Rivers Community College

ENV 2101 Principles of Environmental Engineering I

Instructor: Anthony Benoit

Office: Room 201B (860) 885-2386

Fall 01 (Th 6:00-8:45 pm)

 

abenoit@trcc.commnet.edu

http://environmentalet.org/env2101

Homework #2 Due 10/11/2001

Problem

Answer

2.1

(b) 5 mol O2 = 1 mol C3H8
(c) 363.2 g O2
(d) 0.255 m3 O2 and 1.213 m3 air
(e) 0.153 m3 CO2

2.15

pH = 3.16

2.18

(a) 213 mg/L
(b) 62.6 mg/L
(c) Note: Do calculation for 50 mg/L of glucose, C6H12O6
Answer: 53.3 mg/L

2.20

at pH 6: 0.92; at pH 8: 0.104

2.21

9.5*10-7 mg/L

2.23

2.9 g/L; 0.067 M

2.24

pH = 3.76

ENV 2101 Home


Anthony G Benoit  abenoit@trcc.commnet.edu
(860) 885-2386

Revised